3.4.75 \(\int x^2 (a+b x)^{3/2} (A+B x) \, dx\)

Optimal. Leaf size=95 \[ \frac {2 a^2 (a+b x)^{5/2} (A b-a B)}{5 b^4}+\frac {2 (a+b x)^{9/2} (A b-3 a B)}{9 b^4}-\frac {2 a (a+b x)^{7/2} (2 A b-3 a B)}{7 b^4}+\frac {2 B (a+b x)^{11/2}}{11 b^4} \]

________________________________________________________________________________________

Rubi [A]  time = 0.03, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {77} \begin {gather*} \frac {2 a^2 (a+b x)^{5/2} (A b-a B)}{5 b^4}+\frac {2 (a+b x)^{9/2} (A b-3 a B)}{9 b^4}-\frac {2 a (a+b x)^{7/2} (2 A b-3 a B)}{7 b^4}+\frac {2 B (a+b x)^{11/2}}{11 b^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2*(a + b*x)^(3/2)*(A + B*x),x]

[Out]

(2*a^2*(A*b - a*B)*(a + b*x)^(5/2))/(5*b^4) - (2*a*(2*A*b - 3*a*B)*(a + b*x)^(7/2))/(7*b^4) + (2*(A*b - 3*a*B)
*(a + b*x)^(9/2))/(9*b^4) + (2*B*(a + b*x)^(11/2))/(11*b^4)

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int x^2 (a+b x)^{3/2} (A+B x) \, dx &=\int \left (-\frac {a^2 (-A b+a B) (a+b x)^{3/2}}{b^3}+\frac {a (-2 A b+3 a B) (a+b x)^{5/2}}{b^3}+\frac {(A b-3 a B) (a+b x)^{7/2}}{b^3}+\frac {B (a+b x)^{9/2}}{b^3}\right ) \, dx\\ &=\frac {2 a^2 (A b-a B) (a+b x)^{5/2}}{5 b^4}-\frac {2 a (2 A b-3 a B) (a+b x)^{7/2}}{7 b^4}+\frac {2 (A b-3 a B) (a+b x)^{9/2}}{9 b^4}+\frac {2 B (a+b x)^{11/2}}{11 b^4}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.07, size = 68, normalized size = 0.72 \begin {gather*} \frac {2 (a+b x)^{5/2} \left (-48 a^3 B+8 a^2 b (11 A+15 B x)-10 a b^2 x (22 A+21 B x)+35 b^3 x^2 (11 A+9 B x)\right )}{3465 b^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2*(a + b*x)^(3/2)*(A + B*x),x]

[Out]

(2*(a + b*x)^(5/2)*(-48*a^3*B + 35*b^3*x^2*(11*A + 9*B*x) + 8*a^2*b*(11*A + 15*B*x) - 10*a*b^2*x*(22*A + 21*B*
x)))/(3465*b^4)

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.05, size = 83, normalized size = 0.87 \begin {gather*} \frac {2 (a+b x)^{5/2} \left (-693 a^3 B+693 a^2 A b+1485 a^2 B (a+b x)-990 a A b (a+b x)+385 A b (a+b x)^2-1155 a B (a+b x)^2+315 B (a+b x)^3\right )}{3465 b^4} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^2*(a + b*x)^(3/2)*(A + B*x),x]

[Out]

(2*(a + b*x)^(5/2)*(693*a^2*A*b - 693*a^3*B - 990*a*A*b*(a + b*x) + 1485*a^2*B*(a + b*x) + 385*A*b*(a + b*x)^2
- 1155*a*B*(a + b*x)^2 + 315*B*(a + b*x)^3))/(3465*b^4)

________________________________________________________________________________________

fricas [A]  time = 1.10, size = 120, normalized size = 1.26 \begin {gather*} \frac {2 \, {\left (315 \, B b^{5} x^{5} - 48 \, B a^{5} + 88 \, A a^{4} b + 35 \, {\left (12 \, B a b^{4} + 11 \, A b^{5}\right )} x^{4} + 5 \, {\left (3 \, B a^{2} b^{3} + 110 \, A a b^{4}\right )} x^{3} - 3 \, {\left (6 \, B a^{3} b^{2} - 11 \, A a^{2} b^{3}\right )} x^{2} + 4 \, {\left (6 \, B a^{4} b - 11 \, A a^{3} b^{2}\right )} x\right )} \sqrt {b x + a}}{3465 \, b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(B*x+A),x, algorithm="fricas")

[Out]

2/3465*(315*B*b^5*x^5 - 48*B*a^5 + 88*A*a^4*b + 35*(12*B*a*b^4 + 11*A*b^5)*x^4 + 5*(3*B*a^2*b^3 + 110*A*a*b^4)
*x^3 - 3*(6*B*a^3*b^2 - 11*A*a^2*b^3)*x^2 + 4*(6*B*a^4*b - 11*A*a^3*b^2)*x)*sqrt(b*x + a)/b^4

________________________________________________________________________________________

giac [B]  time = 1.25, size = 350, normalized size = 3.68 \begin {gather*} \frac {2 \, {\left (\frac {231 \, {\left (3 \, {\left (b x + a\right )}^{\frac {5}{2}} - 10 \, {\left (b x + a\right )}^{\frac {3}{2}} a + 15 \, \sqrt {b x + a} a^{2}\right )} A a^{2}}{b^{2}} + \frac {99 \, {\left (5 \, {\left (b x + a\right )}^{\frac {7}{2}} - 21 \, {\left (b x + a\right )}^{\frac {5}{2}} a + 35 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{2} - 35 \, \sqrt {b x + a} a^{3}\right )} B a^{2}}{b^{3}} + \frac {198 \, {\left (5 \, {\left (b x + a\right )}^{\frac {7}{2}} - 21 \, {\left (b x + a\right )}^{\frac {5}{2}} a + 35 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{2} - 35 \, \sqrt {b x + a} a^{3}\right )} A a}{b^{2}} + \frac {22 \, {\left (35 \, {\left (b x + a\right )}^{\frac {9}{2}} - 180 \, {\left (b x + a\right )}^{\frac {7}{2}} a + 378 \, {\left (b x + a\right )}^{\frac {5}{2}} a^{2} - 420 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{3} + 315 \, \sqrt {b x + a} a^{4}\right )} B a}{b^{3}} + \frac {11 \, {\left (35 \, {\left (b x + a\right )}^{\frac {9}{2}} - 180 \, {\left (b x + a\right )}^{\frac {7}{2}} a + 378 \, {\left (b x + a\right )}^{\frac {5}{2}} a^{2} - 420 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{3} + 315 \, \sqrt {b x + a} a^{4}\right )} A}{b^{2}} + \frac {5 \, {\left (63 \, {\left (b x + a\right )}^{\frac {11}{2}} - 385 \, {\left (b x + a\right )}^{\frac {9}{2}} a + 990 \, {\left (b x + a\right )}^{\frac {7}{2}} a^{2} - 1386 \, {\left (b x + a\right )}^{\frac {5}{2}} a^{3} + 1155 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{4} - 693 \, \sqrt {b x + a} a^{5}\right )} B}{b^{3}}\right )}}{3465 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(B*x+A),x, algorithm="giac")

[Out]

2/3465*(231*(3*(b*x + a)^(5/2) - 10*(b*x + a)^(3/2)*a + 15*sqrt(b*x + a)*a^2)*A*a^2/b^2 + 99*(5*(b*x + a)^(7/2
) - 21*(b*x + a)^(5/2)*a + 35*(b*x + a)^(3/2)*a^2 - 35*sqrt(b*x + a)*a^3)*B*a^2/b^3 + 198*(5*(b*x + a)^(7/2) -
21*(b*x + a)^(5/2)*a + 35*(b*x + a)^(3/2)*a^2 - 35*sqrt(b*x + a)*a^3)*A*a/b^2 + 22*(35*(b*x + a)^(9/2) - 180*
(b*x + a)^(7/2)*a + 378*(b*x + a)^(5/2)*a^2 - 420*(b*x + a)^(3/2)*a^3 + 315*sqrt(b*x + a)*a^4)*B*a/b^3 + 11*(3
5*(b*x + a)^(9/2) - 180*(b*x + a)^(7/2)*a + 378*(b*x + a)^(5/2)*a^2 - 420*(b*x + a)^(3/2)*a^3 + 315*sqrt(b*x +
a)*a^4)*A/b^2 + 5*(63*(b*x + a)^(11/2) - 385*(b*x + a)^(9/2)*a + 990*(b*x + a)^(7/2)*a^2 - 1386*(b*x + a)^(5/
2)*a^3 + 1155*(b*x + a)^(3/2)*a^4 - 693*sqrt(b*x + a)*a^5)*B/b^3)/b

________________________________________________________________________________________

maple [A]  time = 0.01, size = 71, normalized size = 0.75 \begin {gather*} \frac {2 \left (b x +a \right )^{\frac {5}{2}} \left (315 B \,b^{3} x^{3}+385 A \,b^{3} x^{2}-210 B a \,b^{2} x^{2}-220 A a \,b^{2} x +120 B \,a^{2} b x +88 A \,a^{2} b -48 B \,a^{3}\right )}{3465 b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*x+a)^(3/2)*(B*x+A),x)

[Out]

2/3465*(b*x+a)^(5/2)*(315*B*b^3*x^3+385*A*b^3*x^2-210*B*a*b^2*x^2-220*A*a*b^2*x+120*B*a^2*b*x+88*A*a^2*b-48*B*
a^3)/b^4

________________________________________________________________________________________

maxima [A]  time = 0.83, size = 77, normalized size = 0.81 \begin {gather*} \frac {2 \, {\left (315 \, {\left (b x + a\right )}^{\frac {11}{2}} B - 385 \, {\left (3 \, B a - A b\right )} {\left (b x + a\right )}^{\frac {9}{2}} + 495 \, {\left (3 \, B a^{2} - 2 \, A a b\right )} {\left (b x + a\right )}^{\frac {7}{2}} - 693 \, {\left (B a^{3} - A a^{2} b\right )} {\left (b x + a\right )}^{\frac {5}{2}}\right )}}{3465 \, b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)^(3/2)*(B*x+A),x, algorithm="maxima")

[Out]

2/3465*(315*(b*x + a)^(11/2)*B - 385*(3*B*a - A*b)*(b*x + a)^(9/2) + 495*(3*B*a^2 - 2*A*a*b)*(b*x + a)^(7/2) -
693*(B*a^3 - A*a^2*b)*(b*x + a)^(5/2))/b^4

________________________________________________________________________________________

mupad [B]  time = 0.07, size = 85, normalized size = 0.89 \begin {gather*} \frac {\left (6\,B\,a^2-4\,A\,a\,b\right )\,{\left (a+b\,x\right )}^{7/2}}{7\,b^4}+\frac {2\,B\,{\left (a+b\,x\right )}^{11/2}}{11\,b^4}+\frac {\left (2\,A\,b-6\,B\,a\right )\,{\left (a+b\,x\right )}^{9/2}}{9\,b^4}-\frac {\left (2\,B\,a^3-2\,A\,a^2\,b\right )\,{\left (a+b\,x\right )}^{5/2}}{5\,b^4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(A + B*x)*(a + b*x)^(3/2),x)

[Out]

((6*B*a^2 - 4*A*a*b)*(a + b*x)^(7/2))/(7*b^4) + (2*B*(a + b*x)^(11/2))/(11*b^4) + ((2*A*b - 6*B*a)*(a + b*x)^(
9/2))/(9*b^4) - ((2*B*a^3 - 2*A*a^2*b)*(a + b*x)^(5/2))/(5*b^4)

________________________________________________________________________________________

sympy [B]  time = 10.02, size = 240, normalized size = 2.53 \begin {gather*} \frac {2 A a \left (\frac {a^{2} \left (a + b x\right )^{\frac {3}{2}}}{3} - \frac {2 a \left (a + b x\right )^{\frac {5}{2}}}{5} + \frac {\left (a + b x\right )^{\frac {7}{2}}}{7}\right )}{b^{3}} + \frac {2 A \left (- \frac {a^{3} \left (a + b x\right )^{\frac {3}{2}}}{3} + \frac {3 a^{2} \left (a + b x\right )^{\frac {5}{2}}}{5} - \frac {3 a \left (a + b x\right )^{\frac {7}{2}}}{7} + \frac {\left (a + b x\right )^{\frac {9}{2}}}{9}\right )}{b^{3}} + \frac {2 B a \left (- \frac {a^{3} \left (a + b x\right )^{\frac {3}{2}}}{3} + \frac {3 a^{2} \left (a + b x\right )^{\frac {5}{2}}}{5} - \frac {3 a \left (a + b x\right )^{\frac {7}{2}}}{7} + \frac {\left (a + b x\right )^{\frac {9}{2}}}{9}\right )}{b^{4}} + \frac {2 B \left (\frac {a^{4} \left (a + b x\right )^{\frac {3}{2}}}{3} - \frac {4 a^{3} \left (a + b x\right )^{\frac {5}{2}}}{5} + \frac {6 a^{2} \left (a + b x\right )^{\frac {7}{2}}}{7} - \frac {4 a \left (a + b x\right )^{\frac {9}{2}}}{9} + \frac {\left (a + b x\right )^{\frac {11}{2}}}{11}\right )}{b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(b*x+a)**(3/2)*(B*x+A),x)

[Out]

2*A*a*(a**2*(a + b*x)**(3/2)/3 - 2*a*(a + b*x)**(5/2)/5 + (a + b*x)**(7/2)/7)/b**3 + 2*A*(-a**3*(a + b*x)**(3/
2)/3 + 3*a**2*(a + b*x)**(5/2)/5 - 3*a*(a + b*x)**(7/2)/7 + (a + b*x)**(9/2)/9)/b**3 + 2*B*a*(-a**3*(a + b*x)*
*(3/2)/3 + 3*a**2*(a + b*x)**(5/2)/5 - 3*a*(a + b*x)**(7/2)/7 + (a + b*x)**(9/2)/9)/b**4 + 2*B*(a**4*(a + b*x)
**(3/2)/3 - 4*a**3*(a + b*x)**(5/2)/5 + 6*a**2*(a + b*x)**(7/2)/7 - 4*a*(a + b*x)**(9/2)/9 + (a + b*x)**(11/2)
/11)/b**4

________________________________________________________________________________________